10 questions · Form 4 Additional Mathematics Bab 1: Quadratic Functions
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Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. The graph of f(x) = ax² + bx + c does NOT intersect the x-axis. Which statement must be TRUE?
Answer: D
No intersection with the x-axis means the quadratic equation f(x) = 0 has no real roots, so b² - 4ac < 0.
2. Express f(x) = x² - 6x + 13 in vertex form by completing the square.
Answer: B
f(x) = x² - 6x + (-3)² - (-3)² + 13 = (x - 3)² - 9 + 13 = (x - 3)² + 4.
3. If the quadratic equation x² - px + 9 = 0 has equal roots, find the possible values of p.
Answer: C
Equal roots => b² - 4ac = 0 => (-p)² - 4(1)(9) = 0 => p² - 36 = 0 => p² = 36 => p = ±6.
4. The quadratic function f(x) = (x - p)² + q has a vertex at (-4, -3). What are the values of p and q?
Answer: B
Compare f(x) = (x - p)² + q with vertex (h, k) = (-4, -3): h = p = -4, k = q = -3.
5. Solve the inequality (x - 2)(x - 6) ≥ 0.
Answer: A
Critical values are x = 2 and x = 6. For '≥ 0' with a positive leading coefficient, solution is outside the roots: x ≤ 2 or x ≥ 6.
6. Find the range of values of k for which the equation x² + 4x + k = 0 has two distinct real roots.
Answer: A
Two distinct roots require b² - 4ac > 0 => (4)² - 4(1)(k) > 0 => 16 - 4k > 0 => 4k < 16 => k < 4.
7. Given the quadratic curve f(x) = 3x² + bx + 12 touches the x-axis at a single point, find the positive value of b.
Answer: A
Touches x-axis => b² - 4ac = 0 => b² - 4(3)(12) = 0 => b² - 144 = 0 => b² = 144 => b = 12 (positive value).
8. Find the range of values of x for which f(x) = 2x² - 8x is negative.
Answer: A
Negative means f(x) < 0 => 2x(x - 4) < 0. Critical values are x = 0 and x = 4. Solution: 0 < x < 4.
9. State the y-intercept of the quadratic graph f(x) = -2(x - 1)² + 8.
Answer: B
y-intercept occurs when x = 0: f(0) = -2(0 - 1)² + 8 = -2(1) + 8 = 6. Thus, y-intercept is (0, 6).
10. Find the roots of the quadratic equation 2x² - 5x - 3 = 0.
Answer: A
Factorising gives (2x + 1)(x - 3) = 0 => 2x + 1 = 0 or x - 3 = 0 => x = -12 or x = 3.